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Fix transaction search inequality in Inventory section

Neal Wilson преди 10 години
родител
ревизия
30cf433917
променени са 1 файла, в които са добавени 31 реда и са изтрити 15 реда
  1. 31
    15
      config/Reports/dailyproductiondetail.xml

+ 31
- 15
config/Reports/dailyproductiondetail.xml Целия файл

@@ -312,14 +312,18 @@
312 312
 				output.writeEndElement();
313 313
 				output.writeEndElement();
314 314
 				output.writeStartElement("tbody");
315
-				q = "SELECT DISTINCT item, (SELECT name FROM items WHERE id = item) AS name, (SELECT out FROM coffee_history WHERE id = item) FROM all_transactions WHERE time > '" + dateString + "' AND time < '" + dateString + "'::date + integer '1' ORDER BY name ASC";
315
+				q = "SELECT DISTINCT item, (SELECT name FROM items WHERE id = item) AS name, (SELECT out FROM coffee_history WHERE id = item) FROM all_transactions WHERE time >= '" + dateString + "' AND time < '" + dateString + "'::date + integer '1' ORDER BY name ASC";
316 316
 				query.exec(q)
317 317
 				var subQuery = new QSqlQuery();
318 318
 				var qq;
319 319
 				while(query.next())
320 320
 				{
321
-					output.writeStartElement("tr");
322
-					output.writeTextElement("td", query.value(1));
321
+					var validRow = true;
322
+					var td1 = query.value(1);
323
+					var td2 = 0;
324
+					var td3 = 0;
325
+					var td4 = 0;
326
+					var td5 = query.value(2);
323 327
 					qq = "SELECT balance FROM item_history(" + query.value(0) + ") WHERE time = (SELECT max(time) FROM all_transactions WHERE time <= '" + dateString + "' AND item = " + query.value(0) + ") OR time = (SELECT max(time) FROM all_transactions WHERE time < '" + dateString + "'::date + integer '1' AND item = " + query.value(0) + ") ORDER BY time ASC";
324 328
 					subQuery.exec(qq);
325 329
 					var startValue = "0.0";
@@ -329,48 +333,61 @@
329 333
 						switch(unitBox.currentIndex)
330 334
 						{
331 335
 							case 0:
332
-								output.writeTextElement("td", (subQuery.value(0)/2.2).toFixed(subQuery.value(0).split('.').length > 1 ? subQuery.value(0).split('.')[1].length : 0));
336
+								td2 = (subQuery.value(0)/2.2).toFixed(subQuery.value(0).split('.').length > 1 ? subQuery.value(0).split('.')[1].length : 0);
333 337
 								break;
334 338
 							case 1:
335
-								output.writeTextElement("td", subQuery.value(0));
339
+								td2 = subQuery.value(0);
336 340
 								break;
337 341
 						}
338 342
 						startValue = subQuery.value(0);
339 343
 					}
340 344
 					else
341 345
 					{
342
-						output.writeEmptyElement("td");
346
+						/* This should never happen. */
347
+						validRow = false;
343 348
 					}
344 349
 					if(subQuery.next())
345 350
 					{
346 351
 						switch(unitBox.currentIndex)
347 352
 						{
348 353
 							case 0:
349
-								output.writeTextElement("td", (subQuery.value(0)/2.2).toFixed(subQuery.value(0).split('.').length > 1 ? subQuery.value(0).split('.')[1].length : 0));
354
+								td3 = (subQuery.value(0)/2.2).toFixed(subQuery.value(0).split('.').length > 1 ? subQuery.value(0).split('.')[1].length : 0);
350 355
 								break;
351 356
 							case 1:
352
-								output.writeTextElement("td", subQuery.value(0));
357
+								td3 = subQuery.value(0);
353 358
 								break;
354 359
 						}
355 360
 						endValue = subQuery.value(0);
356 361
 					}
357 362
 					else
358 363
 					{
359
-						output.writeEmptyElement("td");
364
+						/* If only one transaction exists for the current query
365
+						   this is a purchase transaction. Until something is
366
+						   done with the coffee, it should not appear in this
367
+						   section of the report. */
368
+						endValue = startValue;
369
+						validRow = false;
360 370
 					}
361 371
 					var startPrec = startValue.split('.').length > 1 ? startValue.split('.')[1].length : 0;
362 372
 					var endPrec = endValue.split('.').length > 1 ? endValue.split('.')[1].length : 0;
363 373
 					switch(unitBox.currentIndex)
364 374
 					{
365 375
 						case 0:
366
-							output.writeTextElement("td", (Number(endValue/2.2) - Number(startValue/2.2)).toFixed(Math.max(startPrec, endPrec)));
376
+							td4 = (Number(endValue/2.2) - Number(startValue/2.2)).toFixed(Math.max(startPrec, endPrec));
367 377
 							break;
368 378
 						case 1:
369
-							output.writeTextElement("td", (Number(endValue) - Number(startValue)).toFixed(Math.max(startPrec, endPrec)));
379
+							td4 = (Number(endValue) - Number(startValue)).toFixed(Math.max(startPrec, endPrec));
370 380
 							break;
371
-					}					
372
-					output.writeTextElement("td", query.value(2));
373
-					output.writeEndElement();
381
+					}
382
+					if(validRow) {
383
+						output.writeStartElement("tr");
384
+						output.writeTextElement("td", td1);
385
+						output.writeTextElement("td", td2);
386
+						output.writeTextElement("td", td3);
387
+						output.writeTextElement("td", td4);
388
+						output.writeTextElement("td", td5);
389
+						output.writeEndElement();
390
+					}
374 391
 				}
375 392
 				query = query.invalidate();
376 393
 				subQuery = subQuery.invalidate();
@@ -380,7 +397,6 @@
380 397
 				output.writeEndElement();
381 398
 				output.writeEndElement();//End of inventory table
382 399
 				
383
-				
384 400
 				output.writeEndElement();
385 401
 				output.writeEndElement();
386 402
 				output.writeEndDocument();

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